Comments on: An unfingered guitar string is 0.70 m long and is tuned to play E above middle C (330 Hz). How far from the en? http://freebeginnersguitarlessons.com/how-to-play-guitar/an-unfingered-guitar-string-is-0-70-m-long-and-is-tuned-to-play-e-above-middle-c-330-hz-how-far-from-the-en Learn Guitar Fast and Easy Thu, 03 Mar 2011 14:40:22 +0000 hourly 1 http://wordpress.org/?v=3.3 By: Debbie http://freebeginnersguitarlessons.com/how-to-play-guitar/an-unfingered-guitar-string-is-0-70-m-long-and-is-tuned-to-play-e-above-middle-c-330-hz-how-far-from-the-en/comment-page-1#comment-2847 Debbie Sat, 19 Dec 2009 06:55:59 +0000 http://freebeginnersguitarlessons.com/how-to-play-guitar/an-unfingered-guitar-string-is-0-70-m-long-and-is-tuned-to-play-e-above-middle-c-330-hz-how-far-from-the-en#comment-2847 For a string fixed at both ends the fundamental frequency is f1 = v/2L So v/2 = L1*f1 Since the wave speed is constant we obtain for the second frequency v/2 = L2*f2 Putting these together L1*f1 = L2*f2 or L2 = L1*f1/f2 = 0.70m*330/415 = 0.56 m So you must finger the string at 0.70-0.56 = 0.14m from the end<br><b>References : </b><br> For a string fixed at both ends the fundamental frequency is f1 = v/2L

So v/2 = L1*f1 Since the wave speed is constant
we obtain for the second frequency
v/2 = L2*f2

Putting these together L1*f1 = L2*f2 or L2 = L1*f1/f2 = 0.70m*330/415 = 0.56 m

So you must finger the string at 0.70-0.56 = 0.14m from the end
References :

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